What is expand (4/(x+3))(4/(x+3)) ?

The solution to expand (4/(x+3))(4/(x+3)) is (16)/(x^2+6x+9)

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expand (4/(x+3))(4/(x+3))

expand

(\frac{4}{x + 3}) (\frac{4}{x + 3})

\frac{16}{x ^{2} + 6 x + 9}

Solution steps

(\frac{4}{x + 3}) (\frac{4}{x + 3})

Remove parentheses:

(a) = a

= \frac{4}{x + 3} \cdot \frac{4}{x + 3}

Multiply fractions:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{4 \cdot 4}{( x + 3 ) ( x + 3 )}

Multiply the numbers:

4 \cdot 4 = 16

= \frac{16}{( x + 3 ) ( x + 3 )}

(x + 3) (x + 3) = (x + 3)^{2}

= \frac{16}{( x + 3 ) ^{2}}

(x + 3)^{2} = x^{2} + 6 x + 9

= \frac{16}{x ^{2} + 6 x + 9}

\frac{( 3 s - 1 ) ( 3 s - 2 ) ( s - 1 )}{9}

s^{2} - \frac{3}{2} s - 1

\frac{8 s}{( x + 1 ) ( x - 1 ) ( x ^{2} + 4 x + 5 )}

\frac{x + e ^{x} ( 4 + x ^{2} )}{e ^{x} + 4}

(e^{- 5 t} - e^{2 t})^{2}

What is expand (4/(x+3))(4/(x+3)) ?
The solution to expand (4/(x+3))(4/(x+3)) is (16)/(x^2+6x+9)