What is expand sin(x(pi-pi/(2^x))) ?

The solution to expand sin(x(pi-pi/(2^x))) is sin(pix-(pix)/(2^x))

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expand sin(x(pi-pi/(2^x)))

expand

sin (x (π - \frac{π}{2 ^{x}}))

sin (π x - \frac{π x}{2 ^{x}})

Solution steps

sin (x (π - \frac{π}{2 ^{x}}))

Expand

x (π - \frac{π}{2 ^{x}}) : π x - \frac{π x}{2 ^{x}}

= sin (π x - \frac{π x}{2 ^{x}})

4 sin (\frac{π}{4} (x - 3)) + 6

\frac{1}{4} (\frac{1}{2} e^{2 x} - \frac{1}{2} e^{- 2 x})

\frac{( - z - 1 ) ^{3} z}{6}

(x^{'} + h (x))^{2}

\frac{( 2 y - y ^{2} ) ^{3} \cdot y}{3}

What is expand sin(x(pi-pi/(2^x))) ?
The solution to expand sin(x(pi-pi/(2^x))) is sin(pix-(pix)/(2^x))