What is expand (\forall y)(\forall z)(x+y=z) ?

The solution to expand (\forall y)(\forall z)(x+y=z) is \forall ^2yzx+\forall ^2y^2z=z

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expand (\forall y)(\forall z)(x+y=z)

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(\forall y) (\forall z) (x + y = z)

\forall^{2} yz x + \forall^{2} y^{2} z = z

Solution steps

(\forall y) (\forall z) (x + y = z)

= (\forall y) (\forall z) (x + = yz)

Apply the distributive law:

a (b + c) = ab + a c

a = (\forall y) (\forall z), b = x, c = y = z

(\forall y) (\forall z) x + (\forall y) (\forall z) y = z

x (\forall y) (\forall z) + y (\forall y) (\forall z) = z

Expand

x (\forall y) (\forall z) + y (\forall y) (\forall z) : \forall^{2} yz x + \forall^{2} y^{2} z

\forall^{2} yz x + \forall^{2} y^{2} z = z

\frac{7 u ^{4} + 3 u ^{3}}{- u ^{2}}

2 x e^{y^{2} - x^{2}} - 2 x e^{y^{2} - x^{2}} (x^{2} + y^{2})

(x^{2} - x^{4},) 2 + (y^{2} - y^{2}) 2

cos (θ) (sec (θ) - (cos (θ)) = sin (2 θ))

\frac{2 ( x + 3 )}{3}

What is expand (\forall y)(\forall z)(x+y=z) ?
The solution to expand (\forall y)(\forall z)(x+y=z) is \forall ^2yzx+\forall ^2y^2z=z