What is expand cos(θ)(sec(θ)-(cos(θ))=sin(2θ)) ?

The solution to expand cos(θ)(sec(θ)-(cos(θ))=sin(2θ)) is cos(θ)sec(θ)-cos^2(θ)=sin(2θ)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand cos(θ)(sec(θ)-(cos(θ))=sin(2θ))

expand

cos (θ) (sec (θ) - (cos (θ)) = sin (2 θ))

cos (θ) sec (θ) - cos^{2} (θ) = sin (2 θ)

Solution steps

cos (θ) (sec (θ) - (cos (θ)) = sin (2 θ))

= cos (θ) (sec (θ) - = (cos (θ)) sin (2 θ))

Apply the distributive law:

a (b - c) = ab - a c

a = cos (θ), b = sec (θ), c = (cos (θ)) = sin (2 θ)

cos (θ) sec (θ) - cos (θ) (cos (θ)) = sin (2 θ)

Expand

cos (θ) sec (θ) - cos (θ) (cos (θ)) : cos (θ) sec (θ) - cos^{2} (θ)

cos (θ) sec (θ) - cos^{2} (θ) = sin (2 θ)

\frac{2 ( x + 3 )}{3}

\frac{c ( - 2 b d + 2 b c + d ^{2} - c ^{2} )}{2 d}

e^{- t} (D^{2} + 3) - D sin (2 t)

(2 x - 8) d x

x^{'} + y (y - 3)

What is expand cos(θ)(sec(θ)-(cos(θ))=sin(2θ)) ?
The solution to expand cos(θ)(sec(θ)-(cos(θ))=sin(2θ)) is cos(θ)sec(θ)-cos^2(θ)=sin(2θ)