What is expand P(0,-3)yQ(2,3) ?

The solution to expand P(0,-3)yQ(2,3) is 0*(2*3,)PyQ,-3(2*3,)PyQ

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expand P(0,-3)yQ(2,3)

expand

P (0, - 3) y Q (2, 3)

0 \cdot (2 \cdot 3,) P y Q, - 3 (2 \cdot 3,) P y Q

Solution steps

P (0, - 3) y Q (2, 3)

= (0, - 3) (2 \cdot 3,) P y Q

Apply the distributive law:

a (b - c) = ab - a c

a = P y Q (2, 3), b = 0,, c = 3

= P y Q (2, 3) \cdot 0, - P y Q (2, 3) \cdot 3

= 0 \cdot (2 \cdot 3,) P y Q, - 3 (2 \cdot 3,) P y Q

(B + a t^{2}) (π r^{2} + 2 π cr t + π c^{2} t^{2})

9 (5 x + 8 y = - 24)

(- 5, - 3) y (11, 13)

\frac{u ^{3} ( 12 - 17 z ^{5} )}{4 z ^{3}}

((x + 3) - (e^{\frac{2 x}{3}}))^{2}

What is expand P(0,-3)yQ(2,3) ?
The solution to expand P(0,-3)yQ(2,3) is 0*(2*3,)PyQ,-3(2*3,)PyQ