What is expand (x^2-1)ln(x+1)+x ?

The solution to expand (x^2-1)ln(x+1)+x is x^2ln(x+1)-ln(x+1)+x

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expand (x^2-1)ln(x+1)+x

expand

(x^{2} - 1) ln (x + 1) + x

x^{2} ln (x + 1) - ln (x + 1) + x

Solution steps

(x^{2} - 1) ln (x + 1) + x

= ln (x + 1) (x^{2} - 1) + x

Expand

ln (x + 1) (x^{2} - 1) : x^{2} ln (x + 1) - ln (x + 1)

= x^{2} ln (x + 1) - ln (x + 1) + x

\frac{d}{d x} (e^{(20 + 0.5 i) \cdot x})

(1 - cos (x)) d x - (1 - cos (y)) d y

\frac{1}{cos ( x ) ( sec ( x ) - tan ( x ) )}

\frac{4}{( x ^{2} + x ) ( x + 3 ) ( x ^{2} + 4 ) ( x + 2 ) ( x + 4 )}

- \frac{( 2 - x ) ^{2}}{4}

What is expand (x^2-1)ln(x+1)+x ?
The solution to expand (x^2-1)ln(x+1)+x is x^2ln(x+1)-ln(x+1)+x