What is expand-((2-x)^2)/4 ?

The solution to expand-((2-x)^2)/4 is -(x^2)/4+x-1

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expand-((2-x)^2)/4

expand

- \frac{( 2 - x ) ^{2}}{4}

- \frac{x ^{2}}{4} + x - 1

Solution steps

- \frac{( 2 - x ) ^{2}}{4}

(2 - x)^{2} = 4 - 4 x + x^{2}

= - \frac{x ^{2} - 4 x + 4}{4}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{4 - 4 x + x ^{2}}{4} = - (\frac{4}{4}) - (- \frac{4 x}{4}) - (\frac{x ^{2}}{4})

= - (\frac{4}{4}) - (- \frac{4 x}{4}) - (\frac{x ^{2}}{4})

Remove parentheses:

(a) = a, - (- a) = a

= - \frac{4}{4} + \frac{4 x}{4} - \frac{x ^{2}}{4}

Apply rule

\frac{a}{a} = 1

= - 1 + \frac{4 x}{4} - \frac{x ^{2}}{4}

Divide the numbers:

\frac{4}{4} = 1

= - 1 + x - \frac{x ^{2}}{4}

Rewrite in standard form

= - \frac{x ^{2}}{4} + x - 1

\frac{y u ^{2}}{u ∣ u ∣}

cos (0.2)

(3 x^{2} - 2 x y + 2) d x + (6 y^{2} - x^{2} + 3) d y

\frac{d}{d t} ((x) (x^{3} - 3 x y + y^{3}))

π (\frac{x ^{2}}{4} - \frac{ln ( x )}{2})