What is expand (k^4+4k^3+2)/((k+1)^2) ?

The solution to expand (k^4+4k^3+2)/((k+1)^2) is (k^4+4k^3+2)/(k^2+2k+1)

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expand (k^4+4k^3+2)/((k+1)^2)

expand

\frac{k ^{4} + 4 k ^{3} + 2}{( k + 1 ) ^{2}}

\frac{k ^{4} + 4 k ^{3} + 2}{k ^{2} + 2 k + 1}

Solution steps

\frac{k ^{4} + 4 k ^{3} + 2}{( k + 1 ) ^{2}}

(k + 1)^{2} = k^{2} + 2 k + 1

= \frac{k ^{4} + 4 k ^{3} + 2}{k ^{2} + 2 k + 1}

am o i^{2}

\frac{( 2 x + 9 y ) ^{5}}{243}

\frac{x}{( 1.03 - x ) ( 1.56 - x )}

2 (cos (2 t) - sin (2 t) + e^{- 2 t})

\frac{2}{( 2 \cdot s + 1 ) ( s + 1 )}

What is expand (k^4+4k^3+2)/((k+1)^2) ?
The solution to expand (k^4+4k^3+2)/((k+1)^2) is (k^4+4k^3+2)/(k^2+2k+1)