What is expand (4x-1)/(2(2x^2-1)) ?

The solution to expand (4x-1)/(2(2x^2-1)) is (4x-1)/(4x^2-2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (4x-1)/(2(2x^2-1))

expand

\frac{4 x - 1}{2 ( 2 x ^{2} - 1 )}

\frac{4 x - 1}{4 x ^{2} - 2}

Solution steps

\frac{4 x - 1}{2 ( 2 x ^{2} - 1 )}

Expand

2 (2 x^{2} - 1) : 4 x^{2} - 2

= \frac{4 x - 1}{4 x ^{2} - 2}

\frac{11560}{60}

\frac{1}{1 - ( \frac{x}{6} ) ^{3}}

\frac{( x y )}{( x + y ) ^{2}}

f (- 4 e^{x} + ∣ x ∣ - \frac{1}{8}) d x

\frac{5 x ^{2} - 7 x}{( x + 1 ) ( x - 3 )}

What is expand (4x-1)/(2(2x^2-1)) ?
The solution to expand (4x-1)/(2(2x^2-1)) is (4x-1)/(4x^2-2)