What is the d/(dq)(({r}(q,x))(12.5+0.02x)) ?

The d/(dq)(({r}(q,x))(12.5+0.02x)) is (12.5+0.02x) d/(dq)({r}(q,x))

What is the first d/(dq)(({r}(q,x))(12.5+0.02x)) ?

The first d/(dq)(({r}(q,x))(12.5+0.02x)) is (12.5+0.02x) d/(dq)({r}(q,x))

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\frac{d}{d q} ((r (q, x)) (12.5 + 0.02 x))

(12.5 + 0.02 x) \frac{d}{d q} (r (q, x))

Solution steps

\frac{d}{d q} ((r (q, x)) (12.5 + 0.02 x))

Treat

x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= (12.5 + 0.02 x) \frac{d}{d q} (r (q, x))

ln (w + x) \cdot p + ln (w - x) \cdot (1 - p)

\frac{7 x}{( 2 x + 1 ) ( x - 3 ) d x}

(e - 4)^{2}

\frac{12 ( x - 2 ) ^{2}}{6 ( x - 2 ) x + 5}

\frac{( 9 x ^{2} ( x + 1 ) ^{2} )}{4} - (\frac{3 n ( n + 1 )}{2})

What is the d/(dq)(({r}(q,x))(12.5+0.02x)) ?
The d/(dq)(({r}(q,x))(12.5+0.02x)) is (12.5+0.02x) d/(dq)({r}(q,x))
What is the first d/(dq)(({r}(q,x))(12.5+0.02x)) ?
The first d/(dq)(({r}(q,x))(12.5+0.02x)) is (12.5+0.02x) d/(dq)({r}(q,x))