What is expand \sqrt[3]{(x-8)^2}-4 ?

The solution to expand \sqrt[3]{(x-8)^2}-4 is \sqrt[3]{x^2-16x+64}-4

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expand \sqrt[3]{(x-8)^2}-4

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Solution steps

(x - 8)^{2} = x^{2} - 16 x + 64

\frac{( 6 + x ) ^{2}}{36}

\frac{a \cdot b}{( s ^{2} \cdot ( b \cdot c + a \cdot c ) + s \cdot a \cdot b )}

- (\frac{( x - 2 ) ^{2}}{8}) + 8

\frac{1}{x ( 1 + x y ^{2} )}

4 - (- 1 - \frac{x ^{2}}{16})

What is expand \sqrt[3]{(x-8)^2}-4 ?
The solution to expand \sqrt[3]{(x-8)^2}-4 is \sqrt[3]{x^2-16x+64}-4