What is expand-(((x-2)^2)/8)+8 ?

The solution to expand-(((x-2)^2)/8)+8 is -(x^2)/8+x/2-1/2+8

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expand-(((x-2)^2)/8)+8

expand

- (\frac{( x - 2 ) ^{2}}{8}) + 8

- \frac{x ^{2}}{8} + \frac{x}{2} - \frac{1}{2} + 8

Solution steps

- (\frac{( x - 2 ) ^{2}}{8}) + 8

Remove parentheses:

(a) = a

= - \frac{( x - 2 ) ^{2}}{8} + 8

(x - 2)^{2} = x^{2} - 4 x + 4

= - \frac{x ^{2} - 4 x + 4}{8} + 8

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{x ^{2} - 4 x + 4}{8} = - (\frac{x ^{2}}{8}) - (- \frac{4 x}{8}) - (\frac{4}{8})

= - (\frac{x ^{2}}{8}) - (- \frac{4 x}{8}) - (\frac{4}{8}) + 8

Remove parentheses:

(a) = a, - (- a) = a

= - \frac{x ^{2}}{8} + \frac{4 x}{8} - \frac{4}{8} + 8

Cancel

\frac{4 x}{8} : \frac{x}{2}

= - \frac{x ^{2}}{8} + \frac{x}{2} - \frac{4}{8} + 8

Cancel

\frac{4}{8} : \frac{1}{2}

= - \frac{x ^{2}}{8} + \frac{x}{2} - \frac{1}{2} + 8

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4 - (- 1 - \frac{x ^{2}}{16})

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(y + y x^{2}) y^{'} (x)

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What is expand-(((x-2)^2)/8)+8 ?
The solution to expand-(((x-2)^2)/8)+8 is -(x^2)/8+x/2-1/2+8