What is expand (y+yx^2)y'(x) ?

The solution to expand (y+yx^2)y'(x) is y'(x)y+x^2y'(x)y

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expand (y+yx^2)y'(x)

expand

(y + y x^{2}) y^{'} (x)

y' (x) y + x^{2} y' (x) y

Solution steps

(y + y x^{2}) y^{'} (x)

= (y + x^{2} y) y^{^{'}} (x)

Apply the distributive law:

a (b + c) = ab + a c

a = y^{'} (x), b = y, c = y x^{2}

= y^{^{'}} (x) y + y^{^{'}} (x) y x^{2}

= y^{^{'}} (x) y + x^{2} y^{^{'}} (x) y

(x - \frac{π}{2}) cos (x)

\frac{j w + 2}{( j w + 4 ) ( j ^{2} w ^{2} - j w + 4 )}

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(\frac{- 28}{4} bi g)^{2} (4 - 28) 2

\frac{d}{d y} ((x) ((5 x + 2 y)^{8}))

What is expand (y+yx^2)y'(x) ?
The solution to expand (y+yx^2)y'(x) is y'(x)y+x^2y'(x)y