What is expand (4(3(3a+b)-(5a-b)))/(12) ?

The solution to expand (4(3(3a+b)-(5a-b)))/(12) is (4a)/3+(4b)/3

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expand (4(3(3a+b)-(5a-b)))/(12)

expand

\frac{4 ( 3 ( 3 a + b ) - ( 5 a - b ) )}{12}

\frac{4 a}{3} + \frac{4 b}{3}

Solution steps

\frac{4 ( 3 ( 3 a + b ) - ( 5 a - b ) )}{12}

Cancel the common factor:

4

= \frac{3 ( 3 a + b ) - ( 5 a - b )}{3}

Expand

3 (3 a + b) - (5 a - b) : 4 a + 4 b

= \frac{4 a + 4 b}{3}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{4 a + 4 b}{3} = \frac{4 a}{3} + \frac{4 b}{3}

= \frac{4 a}{3} + \frac{4 b}{3}

, (x - 1) (x - 2) (x - 4)

(p + Δ p + 1)^{2}

\frac{( \frac{3 x}{2} )}{( \frac{3}{x} + 2 )}

(x + 5) + (x + 5) + (3 x - 2)

(v + 1) (v d y + y d v)

What is expand (4(3(3a+b)-(5a-b)))/(12) ?
The solution to expand (4(3(3a+b)-(5a-b)))/(12) is (4a)/3+(4b)/3