What is expand e^{x-3}(x^2-1) ?

The solution to expand e^{x-3}(x^2-1) is e^{x-3}x^2-e^{x-3}

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expand e^{x-3}(x^2-1)

expand

e^{x - 3} (x^{2} - 1)

e^{x - 3} x^{2} - e^{x - 3}

Solution steps

e^{x - 3} (x^{2} - 1)

Apply the distributive law:

a (b - c) = ab - a c

a = e^{x - 3}, b = x^{2}, c = 1

= e^{x - 3} x^{2} - e^{x - 3} \cdot 1

= e^{x - 3} x^{2} - 1 \cdot e^{x - 3}

Multiply:

1 \cdot e^{x - 3} = e^{x - 3}

= e^{x - 3} x^{2} - e^{x - 3}

\frac{1}{2} (x \frac{d y}{d y} + y)

3 e (e + 4)

\frac{( a + b ) ^{2}}{3}

\frac{1}{( 2 - x ) ( 1 + x )}

\frac{( 3 x ^{3} + 2 )}{( ( x - 1 ) ( x ^{2} + 9 ) )}

What is expand e^{x-3}(x^2-1) ?
The solution to expand e^{x-3}(x^2-1) is e^{x-3}x^2-e^{x-3}