What is expand (2r^2+2a^2)/((r+a)^2(r-a)^2) ?

The solution to expand (2r^2+2a^2)/((r+a)^2(r-a)^2) is (2r^2+2a^2)/(r^4-2r^2a^2+a^4)

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expand (2r^2+2a^2)/((r+a)^2(r-a)^2)

expand

\frac{2 r ^{2} + 2 a ^{2}}{( r + a ) ^{2} ( r - a ) ^{2}}

\frac{2 r ^{2} + 2 a ^{2}}{r ^{4} - 2 r ^{2} a ^{2} + a ^{4}}

Solution steps

\frac{2 r ^{2} + 2 a ^{2}}{( r + a ) ^{2} ( r - a ) ^{2}}

(r + a)^{2} = r^{2} + 2 r a + a^{2}

= \frac{2 r ^{2} + 2 a ^{2}}{( r ^{2} + 2 r a + a ^{2} ) ( r - a ) ^{2}}

(r - a)^{2} = r^{2} - 2 r a + a^{2}

= \frac{2 r ^{2} + 2 a ^{2}}{( r ^{2} + 2 r a + a ^{2} ) ( r ^{2} - 2 r a + a ^{2} )}

Expand

(r^{2} + 2 r a + a^{2}) (r^{2} - 2 r a + a^{2}) : r^{4} - 2 r^{2} a^{2} + a^{4}

= \frac{2 r ^{2} + 2 a ^{2}}{r ^{4} - 2 r ^{2} a ^{2} + a ^{4}}

e^{π (b - in)} - e^{- π (b - in)}

\frac{( - 1 ) ^{\frac{1}{π}} ( e ^{4 π} - 1 )}{4 π e ^{2 π}}

\frac{\partial}{\partial x} ((y) ln (5 (x - 1)))

e^{x} (16 x) - e^{x} (8 x^{2} + 2)

(y cos (x y) - 3 x^{2}) d x + (x cos (x y) + 3 y^{2}) d y

What is expand (2r^2+2a^2)/((r+a)^2(r-a)^2) ?
The solution to expand (2r^2+2a^2)/((r+a)^2(r-a)^2) is (2r^2+2a^2)/(r^4-2r^2a^2+a^4)