What is expand ((9x-1)^2)/(36x) ?

The solution to expand ((9x-1)^2)/(36x) is (9x)/4-1/2+1/(36x)

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expand ((9x-1)^2)/(36x)

expand

\frac{( 9 x - 1 ) ^{2}}{36 x}

\frac{9 x}{4} - \frac{1}{2} + \frac{1}{36 x}

Solution steps

\frac{( 9 x - 1 ) ^{2}}{36 x}

(9 x - 1)^{2} = 81 x^{2} - 18 x + 1

= \frac{81 x ^{2} - 18 x + 1}{36 x}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{81 x ^{2} - 18 x + 1}{36 x} = \frac{81 x ^{2}}{36 x} - \frac{18 x}{36 x} + \frac{1}{36 x}

= \frac{81 x ^{2}}{36 x} - \frac{18 x}{36 x} + \frac{1}{36 x}

Cancel

\frac{81 x ^{2}}{36 x} : \frac{9 x}{4}

= \frac{9 x}{4} - \frac{18 x}{36 x} + \frac{1}{36 x}

Cancel

\frac{18 x}{36 x} : \frac{1}{2}

= \frac{9 x}{4} - \frac{1}{2} + \frac{1}{36 x}

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What is expand ((9x-1)^2)/(36x) ?
The solution to expand ((9x-1)^2)/(36x) is (9x)/4-1/2+1/(36x)