What is expand (1-pi)(2+p-q) ?

The solution to expand (1-pi)(2+p-q) is 2+p-q-2pi-pip+piq

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expand (1-pi)(2+p-q)

expand

(1 - π) (2 + p - q)

2 + p - q - 2 π - π p + π q

Solution steps

(1 - π) (2 + p - q)

Distribute parentheses

= 1 \cdot 2 + 1 \cdot p + 1 \cdot (- q) + (- π) \cdot 2 + (- π) p + (- π) (- q)

Apply minus-plus rules

+ (- a) = - a, (- a) (- b) = ab

= 1 \cdot 2 + 1 \cdot p - 1 \cdot q - 2 π - π p + π q

Simplify

1 \cdot 2 + 1 \cdot p - 1 \cdot q - 2 π - π p + π q : 2 + p - q - 2 π - π p + π q

= 2 + p - q - 2 π - π p + π q

a (t) + b

\frac{n ^{n - 1} - 1}{( n - 1 ) ^{2}}

x \cdot (1 - e^{- l \cdot x})

- \frac{2 ( - 3 x ^{2} - 1 )}{( x ^{2} - 1 ) ^{3}}

(x^{2} + y^{2}) d y - 2 x y d x

What is expand (1-pi)(2+p-q) ?
The solution to expand (1-pi)(2+p-q) is 2+p-q-2pi-pip+piq