What is expand 1/((2n+1)!(4n+3)) ?

The solution to expand 1/((2n+1)!(4n+3)) is 1/(4n(2n+1)!+3(2n+1)!)

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expand 1/((2n+1)!(4n+3))

expand

\frac{1}{( 2 n + 1 ) ! ( 4 n + 3 )}

\frac{1}{4 n ( 2 n + 1 ) ! + 3 ( 2 n + 1 ) !}

Solution steps

\frac{1}{( 2 n + 1 ) ! ( 4 n + 3 )}

Expand

(2 n + 1)! (4 n + 3) : 4 n (2 n + 1)! + 3 (2 n + 1)!

= \frac{1}{4 n ( 2 n + 1 ) ! + 3 ( 2 n + 1 ) !}

(1 + d x)^{10}

- t (t + 1) e^{- t} + t

x (x + y^{'} (x))

\frac{\partial}{\partial u} ((x) (u + v)^{2})

ln (x^{2} - 1) (x^{2} - 1)

What is expand 1/((2n+1)!(4n+3)) ?
The solution to expand 1/((2n+1)!(4n+3)) is 1/(4n(2n+1)!+3(2n+1)!)