What is expand (2x(2x+1))/((x-3)(x+1)) ?

The solution to expand (2x(2x+1))/((x-3)(x+1)) is (4x^2+2x)/(x^2-2x-3)

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expand (2x(2x+1))/((x-3)(x+1))

expand

\frac{2 x ( 2 x + 1 )}{( x - 3 ) ( x + 1 )}

\frac{4 x ^{2} + 2 x}{x ^{2} - 2 x - 3}

Solution steps

\frac{2 x ( 2 x + 1 )}{( x - 3 ) ( x + 1 )}

Expand

(x - 3) (x + 1) : x^{2} - 2 x - 3

= \frac{2 x ( 2 x + 1 )}{x ^{2} - 2 x - 3}

Expand

2 x (2 x + 1) : 4 x^{2} + 2 x

= \frac{4 x ^{2} + 2 x}{x ^{2} - 2 x - 3}

\frac{10 x ^{2} + 27}{x ( x + 2 ) ( x + 6 )}

\frac{4 a ^{2}}{b ( 3 a + b )}

\frac{d ^{2}}{d t ^{2}} ((x) (t^{3} - 15 t^{2} + 54 t))

sin (t) U (t - \frac{3 π}{2})

\frac{x - 7}{( x + 6 ) ( x - 6 )}

What is expand (2x(2x+1))/((x-3)(x+1)) ?
The solution to expand (2x(2x+1))/((x-3)(x+1)) is (4x^2+2x)/(x^2-2x-3)