What is expand sin(t)U(t-(3pi)/2) ?

The solution to expand sin(t)U(t-(3pi)/2) is tUsin(t)-(3piUsin(t))/2

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expand sin(t)U(t-(3pi)/2)

expand

sin (t) U (t - \frac{3 π}{2})

t U sin (t) - \frac{3 π U sin ( t )}{2}

Solution steps

sin (t) U (t - \frac{3 π}{2})

= U sin (t) (t - \frac{3 π}{2})

Apply the distributive law:

a (b - c) = ab - a c

a = sin (t) U, b = t, c = \frac{3 π}{2}

= sin (t) U t - sin (t) U \frac{3 π}{2}

= t U sin (t) - \frac{3 π}{2} U sin (t)

Simplify

t U sin (t) - \frac{3 π}{2} U sin (t) : t U sin (t) - \frac{3 π U sin ( t )}{2}

= t U sin (t) - \frac{3 π U sin ( t )}{2}

\frac{x - 7}{( x + 6 ) ( x - 6 )}

r (2 r^{2} - a r + a^{2})^{2}

ln x^{2} \frac{x - 2}{x + 3}

(8 + 2 x)^{\frac{- 1}{3}}

\frac{2}{( s + 5 ) ^{2} ( s )}

What is expand sin(t)U(t-(3pi)/2) ?
The solution to expand sin(t)U(t-(3pi)/2) is tUsin(t)-(3piUsin(t))/2