What is expand ((24x-1)(2x-1))/(16) ?

The solution to expand ((24x-1)(2x-1))/(16) is 3x^2-(13x)/8+1/16

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expand ((24x-1)(2x-1))/(16)

expand

\frac{( 24 x - 1 ) ( 2 x - 1 )}{16}

3 x^{2} - \frac{13 x}{8} + \frac{1}{16}

Solution steps

\frac{( 24 x - 1 ) ( 2 x - 1 )}{16}

Expand

(24 x - 1) (2 x - 1) : 48 x^{2} - 26 x + 1

= \frac{48 x ^{2} - 26 x + 1}{16}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{48 x ^{2} - 26 x + 1}{16} = \frac{48 x ^{2}}{16} - \frac{26 x}{16} + \frac{1}{16}

= \frac{48 x ^{2}}{16} - \frac{26 x}{16} + \frac{1}{16}

Divide the numbers:

\frac{48}{16} = 3

= 3 x^{2} - \frac{26 x}{16} + \frac{1}{16}

Cancel

\frac{26 x}{16} : \frac{13 x}{8}

= 3 x^{2} - \frac{13 x}{8} + \frac{1}{16}

(4 a, - 24, 12, 8) - (912 - 93 b)

π (12 ln (2 + 3) - 3)

\frac{2 t y ( y ^{3} - 1 )}{3 ( 1 + t ^{2} )}

\frac{90}{7 ( 2 x - 7 )}

\frac{4}{3 ( - π + 6 )}

What is expand ((24x-1)(2x-1))/(16) ?
The solution to expand ((24x-1)(2x-1))/(16) is 3x^2-(13x)/8+1/16