What is expand-(e^x)/((e^x-1)^2) ?

The solution to expand-(e^x)/((e^x-1)^2) is -(e^x)/(e^{2x)-2e^x+1}

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expand-(e^x)/((e^x-1)^2)

expand

- \frac{e ^{x}}{( e ^{x} - 1 ) ^{2}}

- \frac{e ^{x}}{e ^{2 x} - 2 e ^{x} + 1}

Solution steps

- \frac{e ^{x}}{( e ^{x} - 1 ) ^{2}}

(e^{x} - 1)^{2} = e^{2 x} - 2 e^{x} + 1

= - \frac{e ^{x}}{- 2 e ^{x} + e ^{2 x} + 1}

(1 + sin (t)) d t

3 x + 4 (2 - x = 4 x + 5)

(\frac{3 !}{2 ! 1 !}) (\frac{3}{16})^{1} (\frac{4}{16})^{2}

2 π x - \frac{π}{2} (10 - π x)

- 4 (1.8 (50 a + 3000))

What is expand-(e^x)/((e^x-1)^2) ?
The solution to expand-(e^x)/((e^x-1)^2) is -(e^x)/(e^{2x)-2e^x+1}