What is 1+(0.213(z+0.8466))/((z-1)(z-0.6065)) ?

The solution to 1+(0.213(z+0.8466))/((z-1)(z-0.6065)) is (z^2-1.3935z+0.7868258)/((z-1)(z-0.6065))

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simplify 1+(0.213(z+0.8466))/((z-1)(z-0.6065))

simplify

1 + \frac{0.213 ( z + 0.8466 )}{( z - 1 ) ( z - 0.6065 )}

\frac{z ^{2} - 1.3935 z + 0.7868258}{( z - 1 ) ( z - 0.6065 )}

Solution steps

1 + \frac{0.213 ( z + 0.8466 )}{( z - 1 ) ( z - 0.6065 )}

Apply the fraction rule:

1 + \frac{b}{c} = \frac{c + b}{c}

= \frac{( z - 1 ) ( z - 0.6065 ) + 0.213 ( z + 0.8466 )}{( z - 1 ) ( z - 0.6065 )}

Simplify

(z - 1) (z - 0.6065) + 0.213 (z + 0.8466) : z^{2} - 1.3935 z + 0.7868258

= \frac{z ^{2} - 1.3935 z + 0.7868258}{( z - 1 ) ( z - 0.6065 )}

\frac{- 3 a ^{2} x ( a - x ) ^{2} - 3 x z ^{2} ( a - x ) ^{2}}{2}

π (- 128 ln (3) + \frac{808}{3})

- \frac{2 x}{2 x + 3} + ln ∣ 2 x + 3 ∣ - \frac{3}{2 ( 2 x + 3 )}

(\frac{x}{4} - \frac{2 x}{5} = \frac{x + 2}{20} - \frac{x + 1}{10}) \cdot 2

(a - 4 a x)^{2} + (b + 2 b x)^{2}

What is 1+(0.213(z+0.8466))/((z-1)(z-0.6065)) ?
The solution to 1+(0.213(z+0.8466))/((z-1)(z-0.6065)) is (z^2-1.3935z+0.7868258)/((z-1)(z-0.6065))