What is expand-(2x)/(2x+3)+ln|2x+3|-3/(2(2x+3)) ?

The solution to expand-(2x)/(2x+3)+ln|2x+3|-3/(2(2x+3)) is -(2x)/(2x+3)+ln|2x+3|-3/(4x+6)

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expand-(2x)/(2x+3)+ln|2x+3|-3/(2(2x+3))

expand

- \frac{2 x}{2 x + 3} + ln ∣ 2 x + 3 ∣ - \frac{3}{2 ( 2 x + 3 )}

- \frac{2 x}{2 x + 3} + ln ∣ 2 x + 3 ∣ - \frac{3}{4 x + 6}

Solution steps

- \frac{2 x}{2 x + 3} + ln ∣ 2 x + 3 ∣ - \frac{3}{2 ( 2 x + 3 )}

Expand

2 (2 x + 3) : 4 x + 6

= - \frac{2 x}{2 x + 3} + ln ∣ 2 x + 3 ∣ - \frac{3}{4 x + 6}

(\frac{x}{4} - \frac{2 x}{5} = \frac{x + 2}{20} - \frac{x + 1}{10}) \cdot 2

(a - 4 a x)^{2} + (b + 2 b x)^{2}

\frac{z}{( z + 9 ) ^{2}}

e^{3 x} (4 + e^{3 x})^{2}

\frac{d ^{2}}{d x ^{2}} ((y) e^{3 x} (1 + 3 x))

What is expand-(2x)/(2x+3)+ln|2x+3|-3/(2(2x+3)) ?
The solution to expand-(2x)/(2x+3)+ln|2x+3|-3/(2(2x+3)) is -(2x)/(2x+3)+ln|2x+3|-3/(4x+6)