What is expand e^{3x}(4+e^{3x})^2 ?

The solution to expand e^{3x}(4+e^{3x})^2 is 16e^{3x}+8e^{6x}+e^{9x}

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expand e^{3x}(4+e^{3x})^2

expand

e^{3 x} (4 + e^{3 x})^{2}

16 e^{3 x} + 8 e^{6 x} + e^{9 x}

Solution steps

e^{3 x} (4 + e^{3 x})^{2}

(4 + e^{3 x})^{2} = 16 + 8 e^{3 x} + e^{6 x}

= e^{3 x} (8 e^{3 x} + e^{6 x} + 16)

Distribute parentheses

= e^{3 x} \cdot 16 + e^{3 x} \cdot 8 e^{3 x} + e^{3 x} e^{6 x}

= 16 e^{3 x} + 8 e^{3 x} e^{3 x} + e^{3 x} e^{6 x}

Simplify

16 e^{3 x} + 8 e^{3 x} e^{3 x} + e^{3 x} e^{6 x} : 16 e^{3 x} + 8 e^{6 x} + e^{9 x}

= 16 e^{3 x} + 8 e^{6 x} + e^{9 x}

\frac{d ^{2}}{d x ^{2}} ((y) e^{3 x} (1 + 3 x))

2 π (\frac{2}{9} - \frac{1}{18})

\frac{1}{( x - 6 ) ^{3}}

\frac{1}{π} [+ 2 - (- 1)^{n} + \frac{π ^{2}}{2} - e^{π}]

P (6, - 2) y Q (- 8, 4)

What is expand e^{3x}(4+e^{3x})^2 ?
The solution to expand e^{3x}(4+e^{3x})^2 is 16e^{3x}+8e^{6x}+e^{9x}