What is the answer to 2x(x+3)+(3-x)^2=3x(x+1) ?

The answer to 2x(x+3)+(3-x)^2=3x(x+1) is x=3

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2x(x+3)+(3-x)^2=3x(x+1)

2 x (x + 3) + (3 - x)^{2} = 3 x (x + 1)

x = 3

Solution steps

2 x (x + 3) + (3 - x)^{2} = 3 x (x + 1)

Expand

2 x (x + 3) + (3 - x)^{2} : 3 x^{2} + 9

Expand

3 x (x + 1) : 3 x^{2} + 3 x

3 x^{2} + 9 = 3 x^{2} + 3 x

Move

9

to the right side

3 x^{2} = 3 x^{2} + 3 x - 9

Subtract

3 x^{2} + 3 x

from both sides

3 x^{2} - (3 x^{2} + 3 x) = 3 x^{2} + 3 x - 9 - (3 x^{2} + 3 x)

Simplify

- 3 x = - 9

Divide both sides by

- 3

x = 3

3 x^{2} - 9 = - 2 x

\frac{9}{- 5} + \frac{- 8}{7}

3 2^{\frac{6}{5}}

- \frac{5}{9} \cdot 4

What is the answer to 2x(x+3)+(3-x)^2=3x(x+1) ?
The answer to 2x(x+3)+(3-x)^2=3x(x+1) is x=3
Solve for x: 2x(x+3)+(3-x)^2=3x(x+1)
The solution is x=3