What is expand (a/(1-bcos(θ)))^2 ?

The solution to expand (a/(1-bcos(θ)))^2 is (a^2)/(1-2bcos(θ)+b^2cos^2(θ))

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expand (a/(1-bcos(θ)))^2

expand

(\frac{a}{1 - b cos ( θ )})^{2}

\frac{a ^{2}}{1 - 2 b cos ( θ ) + b ^{2} cos ^{2} ( θ )}

Solution steps

(\frac{a}{1 - b cos ( θ )})^{2}

Apply exponent rule:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{a ^{2}}{( 1 - b cos ( θ ) ) ^{2}}

(1 - b cos (θ))^{2} = 1 - 2 b cos (θ) + b^{2} cos^{2} (θ)

= \frac{a ^{2}}{1 - 2 b cos ( θ ) + b ^{2} cos ^{2} ( θ )}

f^{''} (x) (2 x + 1)^{5}

\frac{1}{4} x^{2} + \frac{3}{5} x + \frac{9}{5}

7 m^{2} n^{6} \cdot n^{4}

- \frac{3}{( x + 1 )} + \frac{2}{x + 4}

What is expand (a/(1-bcos(θ)))^2 ?
The solution to expand (a/(1-bcos(θ)))^2 is (a^2)/(1-2bcos(θ)+b^2cos^2(θ))