What is expand-3/((x+1))+2/(x+4) ?

The solution to expand-3/((x+1))+2/(x+4) is (-x-10)/(x^2+5x+4)

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expand-3/((x+1))+2/(x+4)

expand

- \frac{3}{( x + 1 )} + \frac{2}{x + 4}

\frac{- x - 10}{x ^{2} + 5 x + 4}

Solution steps

- \frac{3}{x + 1} + \frac{2}{x + 4}

Least Common Multiplier of

x + 1, x + 4 : (x + 1) (x + 4)

Adjust Fractions based on the LCM

= - \frac{3 ( x + 4 )}{( x + 1 ) ( x + 4 )} + \frac{2 ( x + 1 )}{( x + 4 ) ( x + 1 )}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{- 3 ( x + 4 ) + 2 ( x + 1 )}{( x + 1 ) ( x + 4 )}

Expand

(x + 1) (x + 4) : x^{2} + 5 x + 4

= \frac{- 3 ( x + 4 ) + 2 ( x + 1 )}{x ^{2} + 5 x + 4}

Expand

- 3 (x + 4) + 2 (x + 1) : - x - 10

= \frac{- x - 10}{x ^{2} + 5 x + 4}

\frac{( 3 x + 2 ) ( 2 x - 1 )}{( 2 x - 2 ) ( 3 x + 1 )}

0.04 (- 2 e^{- 0.5 t} t - 3 e^{- 0.5 t}) + C

\frac{n ^{2} - n}{2} \cdot \frac{n + 2}{3}

1 + (x^{2} + 1)

\frac{6}{( x + h ) ^{2}}

What is expand-3/((x+1))+2/(x+4) ?
The solution to expand-3/((x+1))+2/(x+4) is (-x-10)/(x^2+5x+4)