What is expand (1+a+a^2)(1-a+a^2)' ?

The solution to expand (1+a+a^2)(1-a+a^2)' is (1-a+a^2)'+a(1-a+a^2)'+a^2(1-a+a^2)'

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expand (1+a+a^2)(1-a+a^2)'

expand

(1 + a + a^{2}) (1 - a + a^{2})^{'}

(1 - a + a^{2})' + a (1 - a + a^{2})' + a^{2} (1 - a + a^{2})'

Solution steps

(1 + a + a^{2}) (1 - a + a^{2})^{'}

Distribute parentheses

= (1 - a + a^{2})^{^{'}} 1 + (1 - a + a^{2})^{^{'}} a + (1 - a + a^{2})^{^{'}} a^{2}

= 1 (1 - a + a^{2})^{^{'}} + a (1 - a + a^{2})^{^{'}} + a^{2} (1 - a + a^{2})^{^{'}}

Multiply:

1 (1 - a + a^{2})^{'} = (1 - a + a^{2})^{'}

= (1 - a + a^{2})^{^{'}} + a (1 - a + a^{2})^{^{'}} + a^{2} (1 - a + a^{2})^{^{'}}

\frac{8 x ^{3} + 48 x ^{2} + 96 x + 64}{4 x ^{2} + 16 x + 16}

\frac{1}{x ( 200 - x )}

\frac{124 ! 2 !}{( 124 - 1 ) !}

\frac{d}{df} ((s) (\frac{4 d}{s ^{3}} - \frac{9 x}{s ^{5}}))

u y^{2} (u d y + y d u)

What is expand (1+a+a^2)(1-a+a^2)' ?
The solution to expand (1+a+a^2)(1-a+a^2)' is (1-a+a^2)'+a(1-a+a^2)'+a^2(1-a+a^2)'