What is expand (y-1)(ln(y-2)+4) ?

The solution to expand (y-1)(ln(y-2)+4) is yln(y-2)+4y-ln(y-2)-4

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expand (y-1)(ln(y-2)+4)

expand

(y - 1) (ln (y - 2) + 4)

y ln (y - 2) + 4 y - ln (y - 2) - 4

Solution steps

(y - 1) (ln (y - 2) + 4)

Apply FOIL method:

(a + b) (c + d) = a c + a d + b c + b d

a = y, b = - 1, c = ln (y - 2), d = 4

= y ln (y - 2) + y \cdot 4 + (- 1) ln (y - 2) + (- 1) \cdot 4

Apply minus-plus rules

+ (- a) = - a

= y ln (y - 2) + 4 y - 1 \cdot ln (y - 2) - 1 \cdot 4

Simplify

y ln (y - 2) + 4 y - 1 \cdot ln (y - 2) - 1 \cdot 4 : y ln (y - 2) + 4 y - ln (y - 2) - 4

= y ln (y - 2) + 4 y - ln (y - 2) - 4

(x^{3} + x^{2} - x)^{10} + 2

\frac{1}{3} (- 1)^{3} + \frac{1}{2} (- 1)^{2} - 2 (- 1)

\frac{25 ( x - 5 )}{x ^{3}}

e^{x} (x - 2)^{3}

What is expand (y-1)(ln(y-2)+4) ?
The solution to expand (y-1)(ln(y-2)+4) is yln(y-2)+4y-ln(y-2)-4