What is expand-((e-x)^2)/(4kt)+e+e^2 ?

The solution to expand-((e-x)^2)/(4kt)+e+e^2 is -(e^2)/(4kt)+(ex)/(2kt)-(x^2)/(4kt)+e+e^2

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expand-((e-x)^2)/(4kt)+e+e^2

expand

- \frac{( e - x ) ^{2}}{4 k t} + e + e^{2}

- \frac{e ^{2}}{4 k t} + \frac{e x}{2 k t} - \frac{x ^{2}}{4 k t} + e + e^{2}

Solution steps

- \frac{( e - x ) ^{2}}{4 k t} + e + e^{2}

(e - x)^{2} = e^{2} - 2 e x + x^{2}

= - \frac{x ^{2} - 2 e x + e ^{2}}{4 k t} + e + e^{2}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{e ^{2} - 2 e x + x ^{2}}{4 k t} = - (\frac{e ^{2}}{4 k t}) - (- \frac{2 e x}{4 k t}) - (\frac{x ^{2}}{4 k t})

= - (\frac{e ^{2}}{4 k t}) - (- \frac{2 e x}{4 k t}) - (\frac{x ^{2}}{4 k t}) + e + e^{2}

Remove parentheses:

(a) = a, - (- a) = a

= - \frac{e ^{2}}{4 k t} + \frac{2 e x}{4 k t} - \frac{x ^{2}}{4 k t} + e + e^{2}

Cancel

\frac{2 e x}{4 k t} : \frac{e x}{2 k t}

= - \frac{e ^{2}}{4 k t} + \frac{e x}{2 k t} - \frac{x ^{2}}{4 k t} + e + e^{2}

\frac{4 ln ( 3 )}{2} (-) - \frac{1}{4} (2^{2} - 4 + 2 ln ∣ 2 + 1 ∣ - 3)

\frac{7 x + 12}{x ( x + 2 )}

(x - 1) e^{c}

- 25 - (- \frac{96}{- 6} - 27) - (- 3)^{2 \circ} 5

x^{(a - b) \cdot (a + b) \cdot (b - c) \cdot (b + c) \cdot (c - a) \cdot (c + a)}

What is expand-((e-x)^2)/(4kt)+e+e^2 ?
The solution to expand-((e-x)^2)/(4kt)+e+e^2 is -(e^2)/(4kt)+(ex)/(2kt)-(x^2)/(4kt)+e+e^2