What is expand (2/3 , 10/3)y(-8/3 ,-10/3) ?

The solution to expand (2/3 , 10/3)y(-8/3 ,-10/3) is -8/3 (2/3*10/3 ,)y,-10/3 (2/3*10/3 ,)y

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expand (2/3 , 10/3)y(-8/3 ,-10/3)

expand

(\frac{2}{3}, \frac{10}{3}) y (- \frac{8}{3}, - \frac{10}{3})

- \frac{8}{3} (\frac{2}{3} \cdot \frac{10}{3},) y, - \frac{10}{3} (\frac{2}{3} \cdot \frac{10}{3},) y

Solution steps

(\frac{2}{3}, \frac{10}{3}) y (- \frac{8}{3}, - \frac{10}{3})

= (\frac{2}{3} \cdot \frac{10}{3},) (- \frac{8}{3}, - \frac{10}{3}) y

Apply the distributive law:

a (b - c) = ab - a c

a = (\frac{2}{3}, \frac{10}{3}) y, b = - \frac{8}{3},, c = \frac{10}{3}

= (\frac{2}{3}, \frac{10}{3}) y (- \frac{8}{3},) - (\frac{2}{3}, \frac{10}{3}) y \frac{10}{3}

Apply minus-plus rules

+ (- a) = - a

= - \frac{8}{3} (\frac{2}{3} \cdot \frac{10}{3},) y, - \frac{10}{3} (\frac{2}{3} \cdot \frac{10}{3},) y

\frac{( n + 1 ) n ( n - 1 )}{6}

\frac{4 s}{( L ( 4 s ^{2} + 1 ) )}

1 0^{0.7}

y + 4^{3}

108 + (- 36) - 72

What is expand (2/3 , 10/3)y(-8/3 ,-10/3) ?
The solution to expand (2/3 , 10/3)y(-8/3 ,-10/3) is -8/3 (2/3*10/3 ,)y,-10/3 (2/3*10/3 ,)y