What is expand 3/2 (y=1)^2-3y(y+1) ?

The solution to expand 3/2 (y=1)^2-3y(y+1) is 3/2 (y=1)^2-3y^2-3y

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expand 3/2 (y=1)^2-3y(y+1)

expand

\frac{3}{2} (y = 1)^{2} - 3 y (y + 1)

\frac{3}{2} (y = 1)^{2} - 3 y^{2} - 3 y

Solution steps

\frac{3}{2} (y = 1)^{2} - 3 y (y + 1)

= \frac{3}{2} (1 = y)^{2} - 3 y (y + 1)

Expand

- 3 y (y + 1) : - 3 y^{2} - 3 y

= \frac{3}{2} (y = 1)^{2} - 3 y^{2} - 3 y

\frac{x ^{2} - 1}{( 1 + x ^{2} ) ^{2}}

(- e^{x} - e^{- x}) \cdot (- e^{x} + e^{- x})

(5 x + 7) (x + 5)^{'}

- x^{3} + (1 + 1 0^{10}) x^{2} - 1 0^{10} x

\frac{x ( x + 8 )}{x ^{2} + 8 x + 16}

What is expand 3/2 (y=1)^2-3y(y+1) ?
The solution to expand 3/2 (y=1)^2-3y(y+1) is 3/2 (y=1)^2-3y^2-3y