What is expand ((2x+6y)*(3x-7y))/(xy) ?

The solution to expand ((2x+6y)*(3x-7y))/(xy) is (6x)/y+4-(42y)/x

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expand ((2x+6y)*(3x-7y))/(xy)

expand

\frac{( 2 x + 6 y ) \cdot ( 3 x - 7 y )}{x y}

\frac{6 x}{y} + 4 - \frac{42 y}{x}

Solution steps

\frac{( 2 x + 6 y ) ( 3 x - 7 y )}{x y}

Expand

(2 x + 6 y) (3 x - 7 y) : 6 x^{2} + 4 x y - 42 y^{2}

= \frac{6 x ^{2} + 4 x y - 42 y ^{2}}{x y}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{6 x ^{2} + 4 x y - 42 y ^{2}}{x y} = \frac{6 x ^{2}}{x y} + \frac{4 x y}{x y} - \frac{42 y ^{2}}{x y}

= \frac{6 x ^{2}}{x y} + \frac{4 x y}{x y} - \frac{42 y ^{2}}{x y}

Cancel

\frac{6 x ^{2}}{x y} : \frac{6 x}{y}

= \frac{6 x}{y} + \frac{4 x y}{x y} - \frac{42 y ^{2}}{x y}

Cancel

\frac{4 x y}{x y} : 4

= \frac{6 x}{y} + 4 - \frac{42 y ^{2}}{x y}

Cancel

\frac{42 y ^{2}}{x y} : \frac{42 y}{x}

= \frac{6 x}{y} + 4 - \frac{42 y}{x}

5 (\frac{1}{5} x - 5 = 10) 5

y \cdot e^{x 2 - x} \cdot (2 - 1)

(x^{'} - 10) (x^{2} - 1)

e^{x (x - 11)}

- (\frac{1}{6} \cdot lo g_{2} (\frac{1}{6}) + \frac{5}{6} \cdot lo g_{2} (\frac{5}{6}))

What is expand ((2x+6y)*(3x-7y))/(xy) ?
The solution to expand ((2x+6y)*(3x-7y))/(xy) is (6x)/y+4-(42y)/x