What is expand 2u((2xsin(ln(x))+xcos(ln(x)))) ?

The solution to expand 2u((2xsin(ln(x))+xcos(ln(x)))) is 4uxsin(ln(x))+2uxcos(ln(x))

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expand 2u((2xsin(ln(x))+xcos(ln(x))))

expand

2 u ((2 x sin (ln (x)) + x cos (ln (x))))

4 ux sin (ln (x)) + 2 ux cos (ln (x))

Solution steps

2 u ((2 x sin (ln (x)) + x cos (ln (x))))

Remove parentheses:

(a) = a

= 2 u (2 x sin (ln (x)) + x cos (ln (x)))

Apply the distributive law:

a (b + c) = ab + a c

a = 2 u, b = 2 x sin (ln (x)), c = x cos (ln (x))

= 2 u \cdot 2 x sin (ln (x)) + 2 ux cos (ln (x))

= 2 \cdot 2 ux sin (ln (x)) + 2 ux cos (ln (x))

Multiply the numbers:

2 \cdot 2 = 4

= 4 ux sin (ln (x)) + 2 ux cos (ln (x))

\frac{( \frac{R cs + 1}{c} ) I}{cs}

(x^{2} + x + 1) e^{x}

\frac{6 + 26 x - x ^{2}}{( 2 x - 1 ) ( x + 2 ) ^{2}}

\frac{1}{( 2 s + 1 ) ( s + 1 )}

π \cdot sin (b) \cdot k \cdot (cos^{2} (a) + 2 \cdot cos (a) + k^{2})

What is expand 2u((2xsin(ln(x))+xcos(ln(x)))) ?
The solution to expand 2u((2xsin(ln(x))+xcos(ln(x)))) is 4uxsin(ln(x))+2uxcos(ln(x))