What is expand P(-1,5)A(2,1)yB(3,-2) ?

The solution to expand P(-1,5)A(2,1)yB(3,-2) is 3(-1*5,)(2*1,)ABPy,-2(-1*5,)(2*1,)ABPy

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expand P(-1,5)A(2,1)yB(3,-2)

expand

P (- 1, 5) A (2, 1) y B (3, - 2)

3 (- 1 \cdot 5,) (2 \cdot 1,) A BP y, - 2 (- 1 \cdot 5,) (2 \cdot 1,) A BP y

Solution steps

P (- 1, 5) A (2, 1) y B (3, - 2)

= (- 1 \cdot 5,) (2 \cdot 1,) (3, - 2) A BP y

Apply the distributive law:

a (b - c) = ab - a c

a = P (- 1, 5) A (2, 1) y B, b = 3,, c = 2

= P (- 1, 5) A (2, 1) y B \cdot 3, - P (- 1, 5) A (2, 1) y B \cdot 2

= 3 (- 1 \cdot 5,) (2 \cdot 1,) A BP y, - 2 (- 1 \cdot 5,) (2 \cdot 1,) A BP y

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What is expand P(-1,5)A(2,1)yB(3,-2) ?
The solution to expand P(-1,5)A(2,1)yB(3,-2) is 3(-1*5,)(2*1,)ABPy,-2(-1*5,)(2*1,)ABPy