What is expand 1/((x)(x-1)(x+6)) ?

The solution to expand 1/((x)(x-1)(x+6)) is 1/(x^3+5x^2-6x)

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expand 1/((x)(x-1)(x+6))

expand

\frac{1}{( x ) ( x - 1 ) ( x + 6 )}

\frac{1}{x ^{3} + 5 x ^{2} - 6 x}

Solution steps

\frac{1}{( x ) ( x - 1 ) ( x + 6 )}

Remove parentheses:

(a) = a

= \frac{1}{x ( x - 1 ) ( x + 6 )}

Expand

x (x - 1) (x + 6) : x^{3} + 5 x^{2} - 6 x

= \frac{1}{x ^{3} + 5 x ^{2} - 6 x}

d x (\frac{10}{z ^{2}} - \frac{4}{z ^{6}})

(6 x^{2}) (e^{- 2 x}) + (2 x^{3} - 1) (- 2 e^{- 2 x})

(\frac{2 x}{y ^{2}})^{5}

\frac{( 1 - cos ( z ) )}{( z ^{3} ( z - 3 ) )}

(- 15)^{3} (4)^{3} + [(- 5)^{2}]^{2}

What is expand 1/((x)(x-1)(x+6)) ?
The solution to expand 1/((x)(x-1)(x+6)) is 1/(x^3+5x^2-6x)