What are the solutions to the equation (5x-3)^2=9 ?

The solutions to the equation (5x-3)^2=9 are x= 6/5 ,x=0

Find the zeros of (5x-3)^2=9

The zeros of (5x-3)^2=9 are x= 6/5 ,x=0

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(5 x - 3)^{2} = 9

x = \frac{6}{5}, x = 0

Decimal Notation

x = 1.2, x = 0

Solution steps

(5 x - 3)^{2} = 9

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

5 x - 3 = 9 : x = \frac{6}{5}

Solve

5 x - 3 = - 9 : x = 0

The solutions to the quadratic equation are:

x = \frac{6}{5}, x = 0

x^{2} + 1.5 x - 2.5 = 0

x - 1 \leq 3 x + 2 \leq 2 x + 6

4 x = 8

\frac{3 x - 4}{6} + \frac{2 - x}{3} = \frac{1}{2}

\frac{w ^{2} - w - 6}{w - 6} \geq 0

What are the solutions to the equation (5x-3)^2=9 ?
The solutions to the equation (5x-3)^2=9 are x= 6/5 ,x=0
Find the zeros of (5x-3)^2=9
The zeros of (5x-3)^2=9 are x= 6/5 ,x=0