What is the answer to (3x-4)/6+(2-x)/3 = 1/2 ?

The answer to (3x-4)/6+(2-x)/3 = 1/2 is x=3

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(3x-4)/6+(2-x)/3 = 1/2

\frac{3 x - 4}{6} + \frac{2 - x}{3} = \frac{1}{2}

x = 3

Solution steps

\frac{3 x - 4}{6} + \frac{2 - x}{3} = \frac{1}{2}

Multiply by LCM

3 x - 4 + 2 (- x + 2) = 3

Expand

3 x - 4 + 2 (- x + 2) : x

x = 3

\frac{w ^{2} - w - 6}{w - 6} \geq 0

x^{2} + 8 x + 12 > 0

x^{3} - 6 x^{2} - x + 6

e^{x} e^{- 2 x}

x^{2} + 14 x - 38 = 0

What is the answer to (3x-4)/6+(2-x)/3 = 1/2 ?
The answer to (3x-4)/6+(2-x)/3 = 1/2 is x=3
Solve for x: (3x-4)/6+(2-x)/3 = 1/2
The solution is x=3