What is expand (9x+3)/((x-1)(x+1)(x+2)) ?

The solution to expand (9x+3)/((x-1)(x+1)(x+2)) is (9x+3)/(x^3+2x^2-x-2)

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expand (9x+3)/((x-1)(x+1)(x+2))

expand

\frac{9 x + 3}{( x - 1 ) ( x + 1 ) ( x + 2 )}

\frac{9 x + 3}{x ^{3} + 2 x ^{2} - x - 2}

Solution steps

\frac{9 x + 3}{( x - 1 ) ( x + 1 ) ( x + 2 )}

Expand

(x - 1) (x + 1) (x + 2) : x^{3} + 2 x^{2} - x - 2

= \frac{9 x + 3}{x ^{3} + 2 x ^{2} - x - 2}

\frac{2 s ^{2} - 6 s + 1}{s ( s - 3 ) ( s + 1 )}

\frac{π ( 18 \cdot 2 ^{\frac{2}{3}} - 14 )}{15}

7 e^{y} (y^{2} - x^{2})

- x e^{x} + x (3 + x)

\frac{d ^{2}}{d h ^{2}} ((v) ((3 h^{2} + 4)^{\frac{3}{2}} - 8))

What is expand (9x+3)/((x-1)(x+1)(x+2)) ?
The solution to expand (9x+3)/((x-1)(x+1)(x+2)) is (9x+3)/(x^3+2x^2-x-2)