What is expand (f(4x-5+h)-4x-5)/h ?

The solution to expand (f(4x-5+h)-4x-5)/h is (4fx)/h-(5f)/h+f-(4x)/h-5/h

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expand (f(4x-5+h)-4x-5)/h

expand

\frac{f ( 4 x - 5 + h ) - 4 x - 5}{h}

\frac{4 f x}{h} - \frac{5 f}{h} + f - \frac{4 x}{h} - \frac{5}{h}

Solution steps

\frac{f ( 4 x - 5 + h ) - 4 x - 5}{h}

Expand

f (4 x - 5 + h) - 4 x - 5 : 4 f x - 5 f + f h - 4 x - 5

= \frac{4 f x - 5 f + f h - 4 x - 5}{h}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{4 f x - 5 f + f h - 4 x - 5}{h} = \frac{4 f x}{h} - \frac{5 f}{h} + \frac{f h}{h} - \frac{4 x}{h} - \frac{5}{h}

= \frac{4 f x}{h} - \frac{5 f}{h} + \frac{f h}{h} - \frac{4 x}{h} - \frac{5}{h}

Cancel

\frac{f h}{h} : f

= \frac{4 f x}{h} - \frac{5 f}{h} + f - \frac{4 x}{h} - \frac{5}{h}

cos (x) d x + (1 + \frac{2}{y}) sin (x)

\frac{3 ( - t ^{4} + 12 t ^{2} - 12 )}{2 t ^{2}}

(1.45) (50)

\frac{\frac{2}{3}}{5}

(x^{2} y - 2 x y + 1) + (- 3 x^{2} y + \frac{1}{2})

What is expand (f(4x-5+h)-4x-5)/h ?
The solution to expand (f(4x-5+h)-4x-5)/h is (4fx)/h-(5f)/h+f-(4x)/h-5/h