What is expand (2(x-3)(3x-4))/((x^2-4)^2) ?

The solution to expand (2(x-3)(3x-4))/((x^2-4)^2) is (6x^2-26x+24)/(x^4-8x^2+16)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (2(x-3)(3x-4))/((x^2-4)^2)

expand

\frac{2 ( x - 3 ) ( 3 x - 4 )}{( x ^{2} - 4 ) ^{2}}

\frac{6 x ^{2} - 26 x + 24}{x ^{4} - 8 x ^{2} + 16}

Solution steps

\frac{2 ( x - 3 ) ( 3 x - 4 )}{( x ^{2} - 4 ) ^{2}}

(x^{2} - 4)^{2} = x^{4} - 8 x^{2} + 16

= \frac{2 ( x - 3 ) ( 3 x - 4 )}{x ^{4} - 8 x ^{2} + 16}

Expand

2 (x - 3) (3 x - 4) : 6 x^{2} - 26 x + 24

= \frac{6 x ^{2} - 26 x + 24}{x ^{4} - 8 x ^{2} + 16}

(x - \frac{1}{x})^{\frac{1}{2}}

\frac{h ( k - t )}{r k t}

\frac{- 2 t ^{5} - 2 t}{( t ^{4} - 1 ) ^{2} ( t ^{2} - 1 )}

A (- 1, 0) B (\frac{3}{2}, - \frac{1}{2})

What is expand (2(x-3)(3x-4))/((x^2-4)^2) ?
The solution to expand (2(x-3)(3x-4))/((x^2-4)^2) is (6x^2-26x+24)/(x^4-8x^2+16)