What is expand (1-t)sL+(1-L)-((1-L)^2)/2+xg ?

The solution to expand (1-t)sL+(1-L)-((1-L)^2)/2+xg is Ls-Lts-1/2-(L^2)/2+xg+1

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expand (1-t)sL+(1-L)-((1-L)^2)/2+xg

expand

(1 - t) s L + (1 - L) - \frac{( 1 - L ) ^{2}}{2} + xg

L s - L t s - \frac{1}{2} - \frac{L ^{2}}{2} + xg + 1

Solution steps

(1 - t) s L + (1 - L) - \frac{( 1 - L ) ^{2}}{2} + xg

= L s (1 - t) + (1 - L) - \frac{( 1 - L ) ^{2}}{2} + xg

Expand

s L (1 - t) : L s - L t s

= L s - L t s + (1 - L) - \frac{( 1 - L ) ^{2}}{2} + xg

Simplify

L s - L t s + (1 - L) - \frac{( 1 - L ) ^{2}}{2} + xg : L s - L t s - \frac{1}{2} - \frac{L ^{2}}{2} + xg + 1

= L s - L t s - \frac{1}{2} - \frac{L ^{2}}{2} + xg + 1

(1 + t (x)^{2}) \frac{d ^{2}}{d t d x} (x) + x

- \frac{3}{4} (e^{- x} - e^{3 x})

\frac{V ( p + h ) ( V p - Vh ) ( h - p )}{p ^{2}}

λ e^{λ t} g (e^{t} - λ e^{t})

What is expand (1-t)sL+(1-L)-((1-L)^2)/2+xg ?
The solution to expand (1-t)sL+(1-L)-((1-L)^2)/2+xg is Ls-Lts-1/2-(L^2)/2+xg+1