What is expand (3-5xe^x)(3x+2) ?

The solution to expand (3-5xe^x)(3x+2) is 9x+6-15e^xx^2-10e^xx

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expand (3-5xe^x)(3x+2)

expand

(3 - 5 x e^{x}) (3 x + 2)

9 x + 6 - 15 e^{x} x^{2} - 10 e^{x} x

Solution steps

(3 - 5 x e^{x}) (3 x + 2)

= (3 - 5 e^{x} x) (3 x + 2)

Apply FOIL method:

(a + b) (c + d) = a c + a d + b c + b d

a = 3, b = - 5 x e^{x}, c = 3 x, d = 2

= 3 \cdot 3 x + 3 \cdot 2 + (- 5 x e^{x}) \cdot 3 x + (- 5 x e^{x}) \cdot 2

Apply minus-plus rules

+ (- a) = - a

= 3 \cdot 3 x + 3 \cdot 2 - 5 \cdot 3 e^{x} xx - 5 \cdot 2 e^{x} x

Simplify

3 \cdot 3 x + 3 \cdot 2 - 5 \cdot 3 e^{x} xx - 5 \cdot 2 e^{x} x : 9 x + 6 - 15 e^{x} x^{2} - 10 e^{x} x

= 9 x + 6 - 15 e^{x} x^{2} - 10 e^{x} x

(b^{2} + c^{2})^{2} + a^{2}

\frac{d ^{2}}{d x ^{2}} ((u (x)) (5.38 + 1.25 \cdot ln (x) - 250 x))

\frac{( e ^{2} - 1 ) I n ^{2}}{2}

2 π (64 - 322)

\frac{6}{( s + 1 ) ( s + 4 ) s ^{4}}

What is expand (3-5xe^x)(3x+2) ?
The solution to expand (3-5xe^x)(3x+2) is 9x+6-15e^xx^2-10e^xx