What is expand ((e^2-1)In^2)/2 ?

The solution to expand ((e^2-1)In^2)/2 is (e^2n^2I)/2-(n^2I)/2

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expand ((e^2-1)In^2)/2

expand

\frac{( e ^{2} - 1 ) I n ^{2}}{2}

\frac{e ^{2} n ^{2} I}{2} - \frac{n ^{2} I}{2}

Solution steps

\frac{( e ^{2} - 1 ) I n ^{2}}{2}

Expand

(e^{2} - 1) I n^{2} : e^{2} n^{2} I - n^{2} I

= \frac{e ^{2} n ^{2} I - n ^{2} I}{2}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{e ^{2} n ^{2} I - n ^{2} I}{2} = \frac{e ^{2} n ^{2} I}{2} - \frac{n ^{2} I}{2}

= \frac{e ^{2} n ^{2} I}{2} - \frac{n ^{2} I}{2}

2 π (64 - 322)

\frac{6}{( s + 1 ) ( s + 4 ) s ^{4}}

(6 x - 6 x^{2}) d x

x (4 x^{2} + 5 x - 3 = 0)

6 (X - 5 = 12)

What is expand ((e^2-1)In^2)/2 ?
The solution to expand ((e^2-1)In^2)/2 is (e^2n^2I)/2-(n^2I)/2