What is expand (f\circ g)(3x+7) ?

The solution to expand (f\circ g)(3x+7) is 3\circ fgx+7\circ fg

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expand (f\circ g)(3x+7)

expand

(f \circ g) (3 x + 7)

3 \circ f gx + 7 \circ f g

Solution steps

(f \circ g) (3 x + 7)

= (\circ f g) (3 x + 7)

Apply the distributive law:

a (b + c) = ab + a c

a = (f \circ g), b = 3 x, c = 7

= (f \circ g) \cdot 3 x + (f \circ g) \cdot 7

= 3 x (\circ f g) + 7 (\circ f g)

Remove parentheses:

(a) = a

= 3 \circ f gx + 7 \circ f g

\frac{x + 1}{2 x} + \frac{2 x + 3}{3 x}

- \frac{8}{n ^{3}} [\frac{n ( n + 1 ) ( 2 n + 1 )}{4}]

x^{4} + (x^{5} + 2) \frac{d y}{d x}

(- 1 - i) e^{t} (cos (t) + i sin (t))

\frac{( 3 - 2 x )}{9}

What is expand (f\circ g)(3x+7) ?
The solution to expand (f\circ g)(3x+7) is 3\circ fgx+7\circ fg