What is expand (-1-i)e^t(cos(t)+isin(t)) ?

The solution to expand (-1-i)e^t(cos(t)+isin(t)) is (-e^tcos(t)+e^tsin(t))+i(-e^tcos(t)-e^tsin(t))

Popular >

expand (-1-i)e^t(cos(t)+isin(t))

expand

(- 1 - i) e^{t} (cos (t) + i sin (t))

(- e^{t} cos (t) + e^{t} sin (t)) + i (- e^{t} cos (t) - e^{t} sin (t))

Solution steps

(- 1 - i) e^{t} (cos (t) + i sin (t))

Expand

(- 1 - i) (cos (t) + i sin (t)) : (- cos (t) + sin (t)) + i (- cos (t) - sin (t))

= e^{t} ((- cos (t) + sin (t)) + i (- cos (t) - sin (t)))

Expand

e^{t} ((- cos (t) + sin (t)) + i (- cos (t) - sin (t))) : (- e^{t} cos (t) + e^{t} sin (t)) + i (- e^{t} cos (t) - e^{t} sin (t))

= (- e^{t} cos (t) + e^{t} sin (t)) + i (- e^{t} cos (t) - e^{t} sin (t))

\frac{( 3 - 2 x )}{9}

sin (\frac{2}{3} (x + 6 π))

\frac{s + e ^{- 2 s}}{s ( s + 1 )}

\frac{d}{d t} ((w) (5 cos^{2} (t) - 10 sin^{2} (t)))

(2 - 10 ln (\frac{4}{3}))^{2}

What is expand (-1-i)e^t(cos(t)+isin(t)) ?
The solution to expand (-1-i)e^t(cos(t)+isin(t)) is (-e^tcos(t)+e^tsin(t))+i(-e^tcos(t)-e^tsin(t))