What is expand (sin(x)+cos(x))e^x ?

The solution to expand (sin(x)+cos(x))e^x is e^xsin(x)+e^xcos(x)

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expand (sin(x)+cos(x))e^x

expand

(sin (x) + cos (x)) e^{x}

e^{x} sin (x) + e^{x} cos (x)

Solution steps

(sin (x) + cos (x)) e^{x}

= e^{x} (sin (x) + cos (x))

Apply the distributive law:

a (b + c) = ab + a c

a = e^{x}, b = sin (x), c = cos (x)

= e^{x} sin (x) + e^{x} cos (x)

(2 e^{4 t} - 4 e^{- 3 t})^{2}

ln (\frac{x ^{8}}{( x - 3 ) ^{4}})

\frac{( 1 - 4 ^{k + 1} )}{- 3}

π (16 - x^{2})^{2}

\frac{6 + 8 i}{4 + ( x + 3 ) i}

What is expand (sin(x)+cos(x))e^x ?
The solution to expand (sin(x)+cos(x))e^x is e^xsin(x)+e^xcos(x)