What is expand ((x+4)(x+5))/((x+1)(x+2)(x-3)) ?

The solution to expand ((x+4)(x+5))/((x+1)(x+2)(x-3)) is (x^2+9x+20)/(x^3-7x-6)

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expand ((x+4)(x+5))/((x+1)(x+2)(x-3))

expand

\frac{( x + 4 ) ( x + 5 )}{( x + 1 ) ( x + 2 ) ( x - 3 )}

\frac{x ^{2} + 9 x + 20}{x ^{3} - 7 x - 6}

Solution steps

\frac{( x + 4 ) ( x + 5 )}{( x + 1 ) ( x + 2 ) ( x - 3 )}

Expand

(x + 1) (x + 2) (x - 3) : x^{3} - 7 x - 6

= \frac{( x + 4 ) ( x + 5 )}{x ^{3} - 7 x - 6}

Expand

(x + 4) (x + 5) : x^{2} + 9 x + 20

= \frac{x ^{2} + 9 x + 20}{x ^{3} - 7 x - 6}

(x - 1) e^{- x} + x + 1

\frac{( x ^{2} + 2 x + 2 )}{( x ^{3} \cdot ( x ^{2} - 1 ) )}

\frac{( x - 1 ) ( 2 x - 5 )}{( x + 3 )}

\frac{( 3 s ^{2} + 4 )}{s ( s ^{2} + 4 )}

121 \cdot 18 - 121 \cdot 8

What is expand ((x+4)(x+5))/((x+1)(x+2)(x-3)) ?
The solution to expand ((x+4)(x+5))/((x+1)(x+2)(x-3)) is (x^2+9x+20)/(x^3-7x-6)